Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
Answer:
True.
Explanation:
An algorithm for a problem provides the set of instructions that are required to solve a problem.It does not provide the full code.It is like an abstract solution of a problem.It is just like a recipe for cooking a dish.It will not cook food for you but can tell you how to cook.
Since it provides the action to be executed hence the answer is True.
I think only II contains an error.
Tricky because, syntactically, all three are correct I.M.O.
However, if the goal is to iterate as many times as lotNumLength, then statement II loops one time too many. This is known as an off-by-one error.
Answer:
Option B is the correct option.
Explanation:
When using SQS the user request to separate a query. The specification specifies that updates on the list may have been transmitted multiple times, but it must be transmitted throughout the sequence in which they appeared, and therefore should require secure, repetitive queue polling.
So, They configure a First In First Out SQS queue and allow long-polling which is suitable for AWS services.
Answer:
C. 1/60
Explanation:
Shutter speed is most commonly measured in fractions of a second, like 1/20 seconds or 1/10 seconds. Some high-end cameras offer shutter speeds as fast as 1/80 seconds. But, shutter speeds can extend to much longer times, generally up to 30 seconds on most cameras.
But in this case C. 1/60 is the answer.