If you play music then you won't get distracted by the outside world or if you study in a quiet room
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1

and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f ×
..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4

when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v ×
× g = mg
and
T = v ×
- v ×
× g
from equation 2
f ×
= f ×
.......................5
now we divide eq 5 by the eq 3

solve irt we get

so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Answer:
-1
Step-by-step explanation:
1x= -1
x= -1
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so

- The length of the fencing is 80 meters, so

Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:

Then substitute for y in the first:

b) To maximize A, find the zero of the first derivative:

So y = (80-40)/2 = 20 meters.
Answer:
The correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.Step-by-step explanation:
The correlation coefficient of a data set describes how closely related two variables are. Correlation coefficients close to positive 1 show a strong positive correlation, while correlation coefficients close to negative 1 show a strong negative correlation. When a correlation coefficient is close to 0, it shows no correlation between the data.
For the given data set, calculate the correlation coefficient using technology.
This r-value is closer to 0 then it is to -1. Thus, the correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.