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3 years ago

15

If an egg is thrown up and off the roof of a 100 foot building with an initial upward velocity of 10 feet per second, how long u

ntil it hits the ground?

1 answer:

Deffense [45]3 years ago

8 0

The equation of the height as a function of time for this case is given by:
h (t) = - 16t ^ 2 + 10t + 100
By the time the egg hits the ground we have:
-16t ^ 2 + 10t + 100 = 0
We look for the roots of the polynomial:
t1 = -2.2069555463432966
t2 = 2.8319555463432966
As it is about time, we use the positive root:
t = 2.83 s
Answer:
it hits the ground at:
t = 2.83 s

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Find the length of the chord made by 3x2 - y2 = 3 and y + x – 5 = 0.

MArishka [77]

Answer:

The correct answer is "9√2 units".

Step-by-step explanation:

The given equations are:

⇒ $3x^2-y^2=3$ ...(equation 1)

⇒ $y+x-5=0$ ...(equation 2)

According to the 2nd equation, we get

⇒ $y+x-5=0$

⇒ $y=5-x$

On substituting the value of "y" in the 1st equation, we get

⇒ $3x^2-y^2=3$

$3x^2-(5-x)^2=3$

$3x^2-(25+x^2-10x)=3$

$2x^2+10x-28=0$

On taking common, we get

$x^2+5x-14=0$

On applying factorization, we get

$x^2+7x-2x-14=0$

$x(x+7)-2(x+7)=0$

$(x+7)(x-2)=0$

$x+7=0$

$x=-7$

or,

$x-2=0$

$x=2$

Now,

The points are:

(-7, 12) = (x₁, y₁)

(2, 3) = (x₂, y₂)

By using the distance formula, the length of chord will be:

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the values in the above formula, we get

= $\sqrt{(2-(-7))^2+(3-12)^2}$

= $\sqrt{(9)^2+(-9)^2}$

= $\sqrt{81+81}$

= $9 \sqrt{2}$ units

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2 years ago

What is the decimal multiplier to increase by 93%?

Sidana [21]

Answer:

0.93

Step-by-step explanation:

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3 years ago

How much is three more than the square of 8?

kari74 [83]

3² equals nine, so the square root of eight has to be less than three.
The square root of eight is 2.82 rounded to the nearest hundredth. So 3 is approximately 0.18 more than the square of eight.

Hope this helps

~DragonGirl :)

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3 years ago

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Expand.If necessary combine like terms.(1+6x)(1-6x)

Anastaziya [24]

Answer:

-36x^2+1

Step-by-step explanation:

(1+6x)(1-6x)

= 1^2(6x)^2

= -36x^2+1

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3 years ago

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Find the horizontal and vertical asymptotes of f(x). f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the

miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

then there is a horizontal asymptote at y = leading coefficient of the

numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ $f(x)=\frac{6x}{x+2}$

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

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