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Wewaii [24]
3 years ago
10

at 8:00 a.m., the outside temperature was –16°. by 9:00 a.m., the outside temperature had dropped 6.5°. what was the outside tem

perature at 9:00 a.m.? a. 22.5° b. 9.5° c. –9.5° d. –22.5°
Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0
<span>D. Because it dropped 6.5 meaning subtract. -16-6.5 = -22.5</span>
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6 0
2 years ago
Read 2 more answers
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5 0
3 years ago
F( y ) = y + y 2 - 3
ExtremeBDS [4]
F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

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f(-4) = -4 + 16 - 3
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f(0) = -3

f(2) = 2 + 2^2 - 3
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f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17



7 0
3 years ago
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