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bixtya [17]
3 years ago
10

A group of 55 friends meets for lunch. They greet each other by exchanging fist bumps. How many fist bumps are exchanged if each

friend must bump with each of the 54 ​others? The total number of fist bumps exchanged is?
Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
55 * 54 = 2,970, hope this helps.
Afina-wow [57]3 years ago
6 0
Well, there's a question I haven't really heard of before. Whatever the case, the total number of fist bumps exchanged is 2,970. (That's a lot of people. That's even more fist bumps. Jeesh.)

Here's how I got that answer : each person exchanges a fist bump with 54 others. So that means each person fist bumps a total of 54 times each. And there are 55 friends in that group, which would mean that you would have to multiply.

54 × 55 = 2,970
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Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a
NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

And then substitute the values in it then

Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

Learn more about probability here

brainly.com/question/24756209

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2 years ago
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yulyashka [42]

Answer:

superheros

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7 0
3 years ago
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vichka [17]
Well since you dont have the graphs posted i can tell u the y-intercept and the slope and you can figure it out from there.

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Makovka662 [10]

Answer:

Pete: 39, Linda: 42

Step-by-step explanation:

Suppose Pete has x dollars. If he has 3 dollars less than Linda, then Linda has 3+x dollars. Together, they have 81 dollars:

x+3+x=81

2x+3=81

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Since Pete has x dollars, and x=39, he has $39.

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<em>I hope this helps! :)</em>

8 0
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