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bixtya [17]
3 years ago
10

A group of 55 friends meets for lunch. They greet each other by exchanging fist bumps. How many fist bumps are exchanged if each

friend must bump with each of the 54 ​others? The total number of fist bumps exchanged is?
Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
55 * 54 = 2,970, hope this helps.
Afina-wow [57]3 years ago
6 0
Well, there's a question I haven't really heard of before. Whatever the case, the total number of fist bumps exchanged is 2,970. (That's a lot of people. That's even more fist bumps. Jeesh.)

Here's how I got that answer : each person exchanges a fist bump with 54 others. So that means each person fist bumps a total of 54 times each. And there are 55 friends in that group, which would mean that you would have to multiply.

54 × 55 = 2,970
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How many solutions does the system of equations below have?<br><br> y= 3x + 4<br> 2y -8 = 6x
Cerrena [4.2K]

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infinitely many solutions (infinite solutions)

Step-by-step explanation:

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   +8    +8

-------------------------------

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Read 2 more answers
A line passes through (-8,3) and (-6,4).What is the equation of the line?
Komok [63]

Answer: The equation of the line that passes through the points

(-8,3) and (-6,4)

is

y=1/2x+7

Step-by-step explanation: First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-8,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-8 and y1=3.

Also, let's call the second point you gave, (-6,4), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-6 and y2=4.

Now, just plug the numbers into the formula for m above, like this:

m=  

4 - 3

-6 - -8

or...

m=  

1

2

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-8,3). When x of the line is -8, y of the line must be 3.

(-6,4). When x of the line is -6, y of the line must be 4.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-8,3) and (-6,4).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-8,3). y=mx+b or 3=1/2 × -8+b, or solving for b: b=3-(1/2)(-8). b=7.

(-6,4). y=mx+b or 4=1/2 × -6+b, or solving for b: b=4-(1/2)(-6). b=7.

See! In both cases we got the same value for b. And this completes our problem.

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