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bixtya [17]
3 years ago
10

A group of 55 friends meets for lunch. They greet each other by exchanging fist bumps. How many fist bumps are exchanged if each

friend must bump with each of the 54 ​others? The total number of fist bumps exchanged is?
Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
55 * 54 = 2,970, hope this helps.
Afina-wow [57]3 years ago
6 0
Well, there's a question I haven't really heard of before. Whatever the case, the total number of fist bumps exchanged is 2,970. (That's a lot of people. That's even more fist bumps. Jeesh.)

Here's how I got that answer : each person exchanges a fist bump with 54 others. So that means each person fist bumps a total of 54 times each. And there are 55 friends in that group, which would mean that you would have to multiply.

54 × 55 = 2,970
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5 0
3 years ago
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Vending machines can be adjusted to reject coins above and below certain weights. The weights of legal U.S. quarters have a norm
tigry1 [53]

Answer: The percentage of legal quarters will be rejected by the vending machine = 2.275%

Step-by-step explanation:

Given: The weights of legal U.S. quarters have a normal distribution with a mean of 5.67 grams and a standard deviation of 0.07 gram.

Let x be the weights of legal U.S. quarters .

Required probability: P(x5.81)

=P(\dfrac{x-\mu}{\sigma}\dfrac{5.81-5.67}{0.07})\\\\=P(z2)\approx0.02275    \ \ \ [By\  P-value\ calculator]

The percentage of legal quarters will be rejected by the vending machine = 2.275%

5 0
2 years ago
For every 6 cups of flour in bread recipe there are 2 cups of milk
Aloiza [94]

Answer:

3

Step-by-step explanation:

3

7 0
3 years ago
Does a linear equation have no solution, one solution, or infinitely many solutions?
Natasha_Volkova [10]
I think that a linear equation can have no solution, one solution, or infinitely solutions. It just depends on what is the equation. That's what I think

3 0
3 years ago
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40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
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