The velocity when function p(t)=11 is 8 .
According to the question
The position of a car at time t represented by function :
Now,
When function p(t) = 11 , t will be
11 = t²+2t-4
0 = t² + 2t - 15
or
t² +2t-15 = 0
t² +(5-3)t-15 = 0
t² +5t-3t-15 = 0
t(t+5)-3(t+5) = 0
(t-3)(t+5) = 0
t = 3 , -5
as t cannot be -ve as given ( t≥0)
so,
t = 3
Now,
the velocity when p(t)=11
As we know velocity = 
therefore to get the value of velocity from function p(t)
we have to differentiate the function with respect to time
v(t) = 2t + 2
where v(t) = velocity at that time
as t = 3 for p(t)=11
so ,
v(t) = 2t + 2
v(t) = 2*3 + 2
v(t) = 8
Hence, the velocity when function p(t)=11 is 8 .
To know more about function here:
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Newtons first law states that an object will remain still or in straight line. Until acted upon some force!
Answer:
q = 4.04×10^-12C
n = 2.53×10^7
Explanation:
1. Electrostatic force on charge due to electrical field E is F = qE
Gravitational force due to weight of drop of mass M is F = mg, when net force is zero we have to find the charges on the drop.
2. Charge on drop: since gravitational force is acting downward, electric field is acting upward and we equate both equations.
Therefore, Fg = Fe
qe = mg
q = mg/E
q = 3.50×10^-9kg×9.8m/s²/8480N/c
q = 4.04 × 10^-12
3. Number of protons by quantitization law
n = q/e
n = 4.04× 10^-12/8480
n = 2.53× 10^7
For reducing erosion of water banks, "Buffer strips" need to be used
In short, Your Answer would be option A
Hope this helps!
Answer:
0.99m
Explanation:
Firs you calculate the relative velocity between the boat and the wave. The velocity of the boat is 5m/s and the velocity of the wave is given by:
the relative velocity is:
This velocity is used to know which is the distance traveled by the boat after 20 seconds:
Next, you use the general for of a wave:
you take the amplitude as 2.0/2 = 1.0m.
by replacing the values of the parameters in f(x,t) you obtain the vertical displacement of the boat:
