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A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r
2 answers:
Answer:
The time taken by the rock to reach the ground is 0.569 seconds.
Explanation:
Given that,
A student throws a rock horizontally off a 5.0 m tall building, s = 5 m
The initial speed of the rock, u = 6 m/s
We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :
So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.
Answer:
The rock to reach the ground in 0.569 sec.
Explanation:
Given that,
Height = 5.0 m
Speed = 6.0 m/s
A student throws a rock horizontally off a 0.5 m tall building.
This is the distance.
So, s = 0.5 m
We need to calculate the time
Using equation of motion
Where, s = distance
t = time
g = acceleration due to gravity
Put the value into the formula
Neglect the negative value.
Hence, The rock to reach the ground in 0.569 sec.
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Answer
given,
radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m
mass of electron, M = 9.11 x 10⁻³¹ Kg
charge of electron, q₁ = 1.6 x 10⁻¹⁹ C
q₂ = 1.6 x 10⁻¹⁹ C
we know, force between two charges
F = 8.20 x 10⁻⁸ N
b) using newton's second law
F = m a
m a = 8.20 x 10⁻⁸
a = 9 x 10²² m/s²
c) speed of the electron
v² = 4.77 x 10¹²
v = 2.18 x 10⁶ m/s
d) the period of the circular motion.
T = 1.53 x 10⁻¹⁶ s
Explanation:
Given that,
Distance between two long wires, d = 16 cm = 0.16 m
Current in one wire,
Current in wire 2,
The magnetic force per unit length of one wire on the other is given by the following expression as :
The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.