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ad-work [718]
3 years ago
5

Devon wants to build a ramp with the dimensions shown. How much wood does he need?

Mathematics
1 answer:
Margarita [4]3 years ago
3 0

The image of the ramp with dimensions is missing, so i have attached it.

Answer:

680 in² of wood is needed.

Step-by-step explanation:

The way to find how much wood would be needed by devon would be to find the total surface area of the ramp.

From the attached image,

Let's find the area of the 2 triangles first;

A1 = 2(½bh) = bh = 15 x 8 = 120 in²

Area of the slant rectangular portion;

A2 = 17 x 14 = 238 in²

Area of the base;

A3 = 15 × 14 = 210 in²

Area of vertical rectangle;

A4 = 8 × 14 = 112 in²

Total Surface Area = A1 + A2 + A3 + A4 = 120 + 238 + 210 + 112 = 680 in²

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Otrada [13]

Answer:

10

Step-by-step explanation:

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3 years ago
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The yoga instructor at Universe Fitness spent $1,925 on 200 items for the upcoming yoga seminar. He purchased yoga mats for $12.
Alex17521 [72]

Answer:

The auditing book is not accurate

Step-by-step explanation:

25($12.5)+50($8)+125($10)+= $1,925

$312.5 + $400 + $1,250 = $1,925

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4 0
3 years ago
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ICE Princess25 [194]

The LCM of the given numbers have been determined.

<h3>What is LCM ?</h3>

LCM stands for Least Common Multiple .

For two numbers , LCM is the number that is the smallest number of which they both are a factor.

It is asked to determine

LCM of 6 and 9

6 = { 6 , 12 , 18 , 24 , 30 , 36 , 42 .....}

9 = { 9 , 18 ,27 .....}

The LCM of 6 , 9 is 18

LCM of 8 and 12

8 = { 8,16,24,32....}

12 = {12 , 24 ,36....}

The LCM of 8 and 12 is 24

LCM of 4 , 6 and 8

4 = {4 , 8 , 12 , 16 , 20,24,28 ....}

6 = { 6 ,12 ,18,24......}

8 = {8 , 16,24 .....}

The LCM of 4,6 and 8  is 24

The LCM of 6 and 15 is 30  

The LCM of 20 and 30 is  60

The LCM of 25,30 and 75 is 150

The image of the solution is attached .

To know more about LCM

brainly.com/question/20739723

#SPJ1

6 0
2 years ago
Evaluate 3C1.<br><br> a)3<br> b)1<br> c)2<br> d)6
murzikaleks [220]

Answer: Option a) 3

Step-by-step explanation:

The formula for calculating combinations is as follows

nCr = \frac{n!}{r!(n-r)!}

Where "n" is the amount of items in a set and you can choose "r" from them

3C1 reads as: The combination of 1 in 3. You have a set of 3 elements and choose 1 of them.

n = 3\\\\r = 1

So :

3C1=\frac{3!}{1!(3-1)!}\\\\3C1=\frac{3!}{1!*2!}\\\\3C1=\frac{3*2*1}{1*2*1}\\\\3C1=3

5 0
3 years ago
Can someone please take a look at the attachment and tell me what the answer is? Serious answers only please!
siniylev [52]
The solid line indicates that the line itself is included in the solutions.  That the shaded area is to the left, or under, the line means that y≤the line.

To find the equation of the line you first find the slope or m using any two points.

m=(y2-y1)/(x2-x1)  in this case you are given (2,-5) and (-2, 3) so

m=(3--5)/(-2-2)

m=8/-4

m=-2

So far for y≤mx+b we have:

y=-2x+b  using either point we can solve for b, I'll use (2,-5)

-5=-2(2)+b

-5=-4+b

-1=b

So the line is:

y=-2x-1  and since y≤ the line:

y≤-2x-1
5 0
3 years ago
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