The equation of a circle centred at point (m,n) and radius r is given by
<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5
Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0
The equation of the circle is x² + y² - 8x - 6y = 0
Hope it helps!
Answer:
B
Step-by-step explanation:
Just pick B bro it isn't even that hard lol
Answer:
why u sooooooooooo gay
Step-by-step explanation:
Answer:
and 
Step-by-step explanation:
Given
Bisector: CD
of Line AB
Required
Apply Pythagoras Theorem
From the question, CD bisects AB and it bisects it at D.
The relationship between AB and CD is given by the attachment
Considering ACD
From the attachment, we have that:
By Pythagoras Theorem, we have
Considering CBD
From the attachment, we have that:
By Pythagoras Theorem, we have:
Answer:
the answer is -5x + -8x-5/2x^2-3
Step-by-step explanation:
:)
