For this case we have the following definitions:
A function is even if, for each x in the domain of f, f (- x) = f (x). The even functions have reflective symmetry through the y-axis.
A function is odd if, for each x in the domain of f, f (- x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.
We then have the following function:
Applying the definitions we have:
Answer:
The function is not odd because it is fulfilled:
Therefore, the function is even.
Answer:
"Multiply the previous value by 2"
Step-by-step explanation:
Let's check the first 2 terms for all the answer choices.
1. Add 
to the previous value:
Doesn't match.
2. Subtract from the previous value:
Doesn't match.
3. Divide the previous value by 2:
Doesn't match.
4. Multiply the previous value by 2:
DOES WORK!
Also, doing the same thing with all the other values would give us matching answer. So this choice is right.
Oh, well if it isn’t slope! I used to do this don’t cheat kiddo figure it out
3x + y = 3
7x + 2y = 1
First isolate one of the variables (x or y) in one of the equations.
Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.
3x + y = 3 Subtract 3x on both sides
3x - 3x + y = 3 - 3x
y = 3 - 3x
7x + 2y = 1
7x + 2(3 - 3x) = 1 [since y = 3 - 3x, you can substitute (3-3x) for "y"]
Multiply/distribute 2 into (3 - 3x)
7x + (3(2) - 3x(2)) = 1
7x + 6 - 6x = 1
x + 6 = 1 Subtract 6 on both sides
x = -5
Now that you know "x", substitute it into one of the equations (I will do both)
3x + y = 3
3(-5) + y = 3 [since x = -5, you can plug in -5 for "x"]
-15 + y = 3 Add 15 on both sides
y = 18
7x + 2y = 1
7(-5) + 2y = 1
-35 + 2y = 1 Add 35 on both sides
2y = 36 Divide 2 on both sides
y = 18
x = -5, y = 18 or (-5, 18)
<h2>
Answer:</h2>
The graph of the circle is given in the image attached
