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Burka [1]
3 years ago
5

Write 4y−10=0 in slope-intercept form

Mathematics
2 answers:
Natalka [10]3 years ago
6 0

Answer:

y= 5/2

Step-by-step explanation:

4y-10=0

+10      +10    <-- add 10 to both sides

4y=10  

4y/4=10/4      <-- divide by 4 to isolate y

y=10/4    

y=5/2            <-- simplify

pogonyaev3 years ago
4 0

Answer:

y=5/2

Step-by-step explanation:

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aivan3 [116]

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We verified that a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

Hence proved

Step-by-step explanation:

Given equation is a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

We have to prove that a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

That is to prove that LHS=RHS

Now taking RHS

\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

=\frac{a+b+c}{2}[a^2-2ab+b^2+b^2-2bc+c^2+c^2-2ac+a^2]  (using (a-b)^2=a^2-2ab+b^2)

=\frac{a+b+c}{2}[2a^2-2ab+2b^2-2bc+2c^2-2ac]  (adding the like terms)

=\frac{a+b+c}{2}[2a^2+2b^2+2c^2-2ab-2bc-2ac]

=\frac{a+b+c}{2}\times 2[a^2+b^2+c^2-ab-bc-ac]

=a+b+c[a^2+b^2+c^2-ab-bc-ac]

Now multiply the each term to another each term in the factor

=a^3+ab^2+ac^2-a^2b-abc-a^2c+ba62+b^3+bc^2-ab^2-b^2c-abc+ca^2+cb^2+c^3-abc-bc^2-ac^2]

=a^3+b^3+c^3-3abc (adding the like terms and other terms getting cancelled)

=a^3+b^3+c^3-3abc =LHS

Therefore LHS=RHS

Therefore a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

Hence proved.

8 0
4 years ago
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