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3 years ago

Simplify the expression 6[8+8](3+7)] ?

Mathematics

2 answers:

krok68 [10]3 years ago

7 0

Answer:

960

Step-by-step explanation:

6[8+8](3+7)

Parentheses first

6[16] (10)

Then multiply from left to right

96*10

960

zheka24 [161]3 years ago

6 0

Answer:

Step-by-step explanation:

6[8+8] [3+7]

Multiply 6 by 8 and 8 by 6

48+48 [3+7]

96 [10]

Have a happy day!!

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Ifound a place that wil give me a 20 % discount if spend over $50.My bill is $75.How much money will I save?help please

Elodia [21]

75 * 20%

75 * .2

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4 years ago

Read 2 more answers

What is x+2318+18=190

astraxan [27]

Your answer is -2,146 because you have to try to get x by itself. So to do that you must subtract 2,318 and 18 from 190 to get your answer.

3 0

3 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off employees at its Sam's Club warehouse unit. App

tatyana61 [14]

Answer:

a) $\bar X = 52$

$Median = 55$

b) $Q_1= \frac{44+44}{2}=44$

$Q_3= \frac{57+60}{2}=58.5$

c) $Range = Max -Min = 69-36=33$

d) $s^2 =100.1429$

$s= \sqrt{100.143}=10.0071$

e) $Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25$

$Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75$

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

Step-by-step explanation:

For this case we have the following dataset:

55 56 44 43 44 56 60 62 57 45 36 38 50 69 65

A total of 15 observations

Part a

We calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^{15} X_i}{15}$

And for this case we got $\bar X = 52$

For the median we ust need to order the data on increasing way like this:

36, 38,43,44,44,45,50,55,56,56,57,60,62,65,69

Since the number of observations is an odd number the median would be on the 8 position from the dataset ordered on this case:

$Median = 55$

Part b

In order to calculate the Q1 we need to select the following data:

36, 38,43,44,44,45,50,55

And the Q1 would be the average between the 4 and 5 positions like this:

$Q_1= \frac{44+44}{2}=44$

And for the Q3 we select these values:

55,56,56,57,60,62,65,69

And the Q3 would be the average between the 4 and 5 positions like this:

$Q_3= \frac{57+60}{2}=58.5$

Part c

The Range is defined as:

$Range = Max -Min = 69-36=33$

Part d

In order to calculate the sample variance we can use the following formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

And if we replace we got:

$s^2 =100.1429$

And the deviation is just the square root of the variance:

$s= \sqrt{100.143}=10.0071$

Part e

For this case we need to find the lower and upper limits for the boxplot given by:

$Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25$

$Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75$

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

4 0

4 years ago

PLEASE HELP!!! give an explanation if you can

Goryan [66]

Here I solved it for you on paper

8 0

3 years ago

What's the equation of the line that's a perpendicular bisector of the segment connecting C (6, –12) and D (10, –8)? ANSWERS: A)

zavuch27 [327]

Answer:

B) y = x + 2

Step-by-step explanation:

Coordinates of point C = $(x_1,y_1)=(6,-12)$

Coordinates of point D= $(x_2,y_2)=(10,-8)$

To find the equation of segment CD

Formula : $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Substitute the values in the formula :

$y-12=\frac{-8+12}{10-6}(x-6)$

y-12=x-6

y=x+6

When two lines are perpendicular to each other the product of their slopes is -1

Let the slope of perpendicular line be x

So, -1 \times x = -1

So, x =1

General equation : y = mx+c

So, Option B has slope = 1

So,the equation of the line that's a perpendicular bisector of the segment connecting C (6, –12) and D (10, –8) is y = x + 2

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3 years ago