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3 years ago

Put 6x-2y=-14 into slope intercept form ( y=mx+b) then graph

Mathematics

1 answer:

RSB [31]3 years ago

5 0

Subtract 6x from both sides
-2y = -6x - 14 Now divide by - 2
-2y/-2 = -6x/-2 - 14/-2 Notice how all the minus signs cancel out.

y = 3x + 7

I'll supply you with the graph (and the table if I can figure out how to do that)

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2 years ago

You do not need to flip the inequality sign when solving the inequality -3t + 7 ≥ 9. True False

nordsb [41]

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3 years ago

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slega [8]

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See the attached

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3 years ago

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I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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3 years ago