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gayaneshka [121]
3 years ago
8

Put 6x-2y=-14 into slope intercept form ( y=mx+b) then graph

Mathematics
1 answer:
RSB [31]3 years ago
5 0
Subtract 6x from both sides
-2y = -6x - 14 Now divide by - 2
-2y/-2 = -6x/-2 - 14/-2 Notice how all the minus signs cancel out.

y = 3x + 7

I'll supply you with the graph (and the table if I can figure out how to do that)

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You do not need to flip the inequality sign when solving the inequality -3t + 7 ≥ 9. True False
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It is False because t is multiplied by a negative number, so to solve for it you will need to divide both sides by -3 which mean you have to flip the sign. 

Hope this helps!
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3 years ago
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I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
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