Answer:
They allowed businesses to operate with few regulations.
Answer:
1/4
Explanation:
Cystic fibrosis is a recessive disorder and therefore, is expressed only in homozygous recessive genotype. Let's assume that the allele "c" is responsible for the disease in the homozygous state. Since the couple already has a child with cystic fibrosis (cc), they both are heterozygous carriers for the disease.
The genotype of male and female each is "Cc". A cross between Cc x Cc gives progeny in the following phenotype ratio=1/4 diseased: 1/2 normal carriers: 1/4 normal. Therefore, the probability of getting a diseased child for them is 1/4.
Answer:
1. codominance Both members of an allelic pair contribute to phenotype producing a mixture of phenotypic traits
2 . Rh factor: An inherited protein found on the surface of the red blood cell membrane
3 . hemophilia: A hereditary condition for bleeding due to the inability to clot properly
4 . holandric gene: A gene located on the Y chromosome in XY species
Explanation:
Codominance occur when a pure breeding White flower crosses with a pure breeding Red flower and gives PINK offspring
Rhesus Factor is an antigen that appears on the surface of red blood cells. it is an important factor to consider during blood transfusion.
Hemophilia is a sex-linked condition where the sufferer is unable to have a blood clot.
Holandric gene can ONLY be passed from males (carriers of XY chromosomes) to their sons
C. Assuming the gametes for red flowering plant is heterozygous and the white is homozygous, it will be all pink
