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Degger [83]
3 years ago
5

What is 312.501 rounded to the nearest whole number? A. 310 B. 311 C. 312 D. 313

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0
313. Anything .5 or higher rounds up to the higher number.
Hope it helps!
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Answer:

I know this aint no clever bro cmon that stuff is easy

Step-by-step explanation:

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Your housing and fixed expenses are $702.38/month. What is your realized income for the month if your expenses account 30%
Ksenya-84 [330]
We are asked to solve for the monthly income given that 30% of it goes to your expenses.
Expenses per month = $702.38
Expenses percent from income = 30% = 0.3
Total income per month  = X

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$702.38 = 30% * X
X = $702.38 / 0.3
X = $2,341.27

The total income is $2,341.27.
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3 years ago
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The table below represents a linear function f(x) and the equation represents a function g(x):
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Answer:

Step-by-step explanation:

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3 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
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