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Degger [83]
3 years ago
5

What is 312.501 rounded to the nearest whole number? A. 310 B. 311 C. 312 D. 313

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0
313. Anything .5 or higher rounds up to the higher number.
Hope it helps!
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(A) it takes 55 pounds of seed to completely plant a 9-acre field. How many pounds of seed are needed per acre?
adell [148]
A: 55 / 9 = 6.11 lbs. of seed (rounded)

B: 37 / 7 = $5.28 per hour (rounded)
7 0
3 years ago
HELP ASAP I will mark brainliest Emmy is flying a drone in a field near her house. She placed the drone on the ground and used t
insens350 [35]

Answer:

It is the one on the bottom right

Step-by-step explanation:

First of all, we have to start at (0,0), so we can cross out the one on the top left and top right, as they does not.

Also, the one on the bottom right does not go back to the ground, though just stays in the air, but the one on the bottom right dows go back to the ground.

So, its the one on the bottom right

4 0
3 years ago
R minus the sum of 4 and p equals
UkoKoshka [18]

Answer:

r - (4 + p)

Step-by-step explanation:

{that's how you write it if that's what you are asking}

4 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
G(n)=n^3+n<br> g(-3)<br> help!
Svetradugi [14.3K]
The question is simply asking you to evaluate the function for an input value of -3. Meaning we plug in -3 for all cases of n. (-3)^3 + (-3). This gives us -27 -3 which is -30. So g(-3)= -30
6 0
2 years ago
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