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Korolek [52]
3 years ago
11

In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8%

more than 1999, find the enrolment in 1998
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

1998= 30,000 students

Step-by-step explanation:

Giving the following information:

In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8% more than 1999, find the enrolment in 1998

<u>First, we need to determine the enrolment in 1999:</u>

1999= 36,612/1.08

1999= 33,900

<u>Now, we can find the enrolment in 1998:</u>

1998= 33,900/1.13

1998= 30,000

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After distributing, which equation is equivalent to -4(3x + 2) = 10a.-12x -8 = 10b.-12x + 8 = 10c.-12x -6 = 10d.-12x + 6 = 1
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Answer:

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Step-by-step explanation:

Given equation is:

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If &lt; A and &lt; B form a linear pair, and &lt; A = x - 13 degrees, and &lt; B = x + 7 degrees, then find x. Select one: a. 12
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The correct value of "x" will be "93".

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then

→ x-13+x+7=180

→             2x -6=180

By adding "6" both sides of the equation, we get

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→                   2x=186

→                     x = \frac{186}{2}

→                     x = 93

Thus "option d" is the right answer.  

Learn more:

brainly.com/question/19152299

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