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Lana71 [14]
3 years ago
10

Someone please help ASAP?

Mathematics
1 answer:
lord [1]3 years ago
7 0

Answer:

(6,-4)

Step-by-step explanation:

Sorry just getting to this now. A little late to be ASAP

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What is the simplest form of this expression?
Dimas [21]

Answer:

(4-m-1)-5

Remove the bracket

= 4-m-1-5

= -2-m

Hope this helps.

7 0
4 years ago
I need help or the answer
m_a_m_a [10]
The answer to your problem would be answer
3 0
3 years ago
In a chemistry lab, you have 2 vinegars. One is 5% acetic acid, and one is 6.5% acetic acid. You want to make 200 ml of a vinega
Iteru [2.4K]
We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f  -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
<span> <span> <span> we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
</span> </span>
Source:
http://www.1728.org/mixture.htm


8 0
3 years ago
2/3 multiplied by (-4 1/3) as a fraction
Rus_ich [418]
The answer is -2 8/9
3 0
3 years ago
Read 2 more answers
Fred’s company is planning a new logo. The diagrams show two similar versions of the planned logo.
seraphim [82]

Answer:

a=7.2*1.5=10.8 cm

b=6.3/1.5=4.2 cm

\pounds 4.48*2.25=\pounds 10.08

Step-by-step explanation:

<u>Proportional Geometric Shapes </u>

A) We are given two similar shapes of a logo. They are to be proportional. We only need to find the proportion ratio of two of them to find the rest of the lengths.

The upper sides have 7.5 cm and 5 cm respectively. This gives us the ratio

\displaystyle r=\frac{7.5}{5}=1.5

Which means all the measures of the smaller logo are 1.5 smaller than those of the larger. This means  

b=6.3/1.5=4.2 cm

a=7.2*1.5=10.8 cm

B) To paint the logos, we need to cover its surface, so the ratio of the surface is 1.5*1.5=2.25

This means the cost to paint the larger logo is  

\pounds 4.48*2.25=\pounds 10.08

5 0
4 years ago
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