Answer:
There are <u>infinite rational </u>numbers between two rational or two irrational number.
#answerwithquality #BAL
Answer:
Step-by-step explanation:
Given
Rectangle:
Length = 2 in
Width = 3 in
Scale Factor = 7
Solving (a):
The side lengths of the new scale is calculated as follows;
New Lengths = Old Lengths * Scale Factor
Solving (b): To go back to the original length
Given that the initial scale factor is 7;
The new scale factor is the reciprocal of the old factor;
Hence;
Answer:
You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:
First, remember how the absolute value works:
IxI = x if x ≥ 0
IxI = -x if x ≤ 0
Then if we have something like:
IxI < B
We can rewrite this as
-B < x < B
Now let's answer the question, here we have the inequality:
I-k -2I < 18
Then we can rewrite this as:
-18 < (-k - 2) < 18
Now let's isolate k:
first, we can add 2 in the 3 parts of the inequality:
-18 + 2 < -k - 2 + 2 < 18 + 2
-16 < -k < 20
Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:
-1*-16 > -1*-k > -1*20
16 > k > -20
Then k can be any value between these two limits.
So the correct options (from the given ones) are:
k = -16
k = -8
k = 0
Answer:
$7075 or 7718
Step-by-step explanation:
91100-6200=84900
84900/11= 7718.18181818 or rounded= 7718
(This is if the december month doesnt count.)
84900/12=7075
(If december is included.)
Answer: the answer has to be a because the other ones are not even close
Step-by-step explanation:
