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LuckyWell [14K]
3 years ago
12

The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

Mathematics
1 answer:
gladu [14]3 years ago
7 0
We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub


p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
p= \frac {(x-6)(x+1)(x+4)}{(x-2)}

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Answer:

46

Step-by-step explanation:

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3 0
3 years ago
An isosceles triangle has an angle that measures 94º. Which other angles could be in that
Nataly [62]

Answer:

43°

Step-by-step explanation:

In a isosceles triangle, two angles HAVE to be equal.

This means that 94 can be one of the angles that are equal, or the angle that is not equal to another angle.

Let's start with the fact that 94 can be one of the angles that are equal. (Note: angles in a triangle add up to 180)

94+94+x=180

188+x=180

There is NOT a possible value for x in this situation, as you cannot have a negative value of an angle. Therefore we must try the other situation where 94 is the angle that is not equal to another angle.

x+x+94=180

2x+94=180

Subtract 94 from both sides

2x=86


Divide both sides by 2

x=43

Therefore the answer is 43°

4 0
2 years ago
A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t
nexus9112 [7]
This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon. 

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s: 

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other: 

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation: 

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation: 

1.1s = 5.1

Last, we divide both sides by 1.1. So s = 4.63. 

This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation: 

2.6s + 7.3
= 2.6 (4.63) + 7.3
= 19.33

1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.
6 0
4 years ago
WILL GIVE BRAINLIEST, RATING, AND THANKS!
Mashutka [201]

-10(-2)+y = 4

20 + y = 4

y = -16

----------------

-10(-1)+y = 4

10 + y = 4

y = -6

----------------

-10(0) + y = 4

0 + y = 4

y = -4

----------------

-10(1)+y = 4

-10 + y = 4

y = 14

----------------

-10(2)+y = 4

-20 + y = 4

y = 24

----------------

I hope thi helps

-ayden

6 0
3 years ago
Read 2 more answers
Johnny has a job that pays $6 per hour plus tips. If Johnny worked 5 hours and made $45, write an equation in point-slope form t
stepladder [879]

Answer:

6*5=30

45-30=15

he made 15$ in tips.

6 0
4 years ago
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