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forsale [732]
3 years ago
12

Calculate the average (arithmetic mean) of the list of numbers shown in the table. (rounded to the nearest tenth)

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Hello!

<h3><u><em>Answer</em></u></h3>

The mean of the numbers shown in the table is C. 50.5

<h3>__________________________________________________</h3><h3><em><u>Explanation</u></em></h3>

To calculate the mean, simply add up all the numbers and divide by the amount of numbers there are in the list.

18 + 55 + 101 + 96 + 55 + 18 + 22 + 23 + 22 + 57 + 88 = 555

There are 11 numbers in the table, so we divide by that.

555 / 11 = 50.45...

Finally, round to the nearest tenth: 50.5

<h3 />
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Hey, do you need to simplify all of them?
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3 years ago
Solve the following proportion for y.<br> y/9 = 8/11<br> Round your answer to the nearest tenth.
jek_recluse [69]
Answer: 6.5

6.5/11 ≈ 8/11
8 0
3 years ago
Solve the following equation<br> x²-10x+25=0
liq [111]

Answer:

X=5

Step-by-step explanation:

You want to factor the left side of the equation

(X-5)(x-5)=0

Set factors that will equal to 0

X-5=0

X=5 is the answer

3 0
2 years ago
The ration of girls to boys is 3 to 4 if there are 48 boys how many girls are there
Luden [163]

Answer:

There is 36 girls.

Step-by-step explanation:

So basically what I did was that since 4×12 is 48 I did 3×12 which gave me 36 :/

4 0
4 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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