Point M is in the exterior of an angle AOB, ray OC is a bisector of this angle. Prove, that the measure of angle MOC is equal to
one-half the sum of the measures of angles AOM and BOM.
1 answer:
Answer:
see the prove below
Step-by-step explanation:
<u>We have to prove that </u><u>MOC=(AOM+BOM)/2</u>
Let Angle AOM=x and AOC=y . => AOB=2y ( because OC is the bisector of AOB)
So MOC= AOM+AOC=x+y
BOM=AOB+AOM=2y +x
AOM+BOM= x+2y+x=2y+2x
(AOM+BOM)/2= (2y+2x)/2=x+y=MOC
The statement is proved
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Step-by-step explanation:
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Step-by-step explanation:
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