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Phantasy [73]
3 years ago
15

What is A decreased by 20% and then increased by 20% of that? Please show your work.

Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Answer: \\ A - 20\%A = A - 0.2A = 0.8A \\ 0.8A + 20\%0.8A = 0.8A + 0.2 \times 0.8A = 0.8 + 0.16A = 0.96A

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Calculate x Give your answer correct to 1 d.p. Х 35° 15 cm<br> it is a trigonometry question.​
OlgaM077 [116]

Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.

So let's do cos(35°) = 15cm / x

cos(35°) = 0.8 (1 dp)

x = 15 cm / cos(35°)

x = 18.3 cm (1 dp)

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Copy and complete the statement using &lt;,&gt;,= |-11 |-10|
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4 years ago
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Simplify the following expression.<br> 343 1/3<br> (Write your answer as an integer.)
aalyn [17]
343^1/3
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3 years ago
Should i give up with math it to hard and i try every time
bekas [8.4K]

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No as hard as math is it’s a great feeling when you get that “OHH I GET IT” moment. And plus if your in school your kinda. Stuck with it anyway

Step-by-step explanation:

6 0
2 years ago
Please help!
erik [133]
For the answer to the question above, 
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3 

<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
5 0
3 years ago
Read 2 more answers
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