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Mars2501 [29]
3 years ago
10

A^2+b^2=1305, a*b=648, a-b=?

Mathematics
2 answers:
luda_lava [24]3 years ago
7 0

a - b is 9

Step-by-step explanation:

  • Step 1: Given a² + b² = 1305, a × b = 648. Find a - b using the identity for (a - b)²

⇒ (a - b)² = a² + b² - 2ab

⇒ (a - b)² = 1305 - 2 × 648 = 1305 - 1296 = 9

⇒ (a - b) = 9

Vadim26 [7]3 years ago
5 0

Answer:

± 3

Step-by-step explanation:

(a-b)^2 = a^2 + b^2 - 2ab

           = 1305 - 2(648)

           = 1305 - 1296

           = 9

\sqrt{(a-b)^{2} = \sqrt{9}

a-b = ± 3

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Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
Maurinko [17]

Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

s= 15.5

And the standard error is given by:

SE = \frac{s}{\sqrt{n}} =3.1

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

z_{\alpha/2}= \pm 0.994

We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

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3 years ago
Sabita made this table to relate two customary units of liquid volume
Pachacha [2.7K]
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3 years ago
Read 2 more answers
HELP PLEASE!!!!!!
wel

Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

<h3>The average annual rate of change</h3>

The given parameters are:

Value in 1990 = $12,500

Value in 2009 = $20,050

The average annual rate of change is then calculated as:

Rate of change = Difference in the values/Difference in the years

So, we have:

Rate of change = (20050 - 12500)/(2009 - 1990)

Evaluate

Rate of change = 397.37

<h3>Pat and cable car</h3>

<u>The complete table of average rate of change</u>

The average rate of change is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

<em>0 - 2 minutes</em>

Pat = (125 - 0)/(2 - 0) = 62.5

Cable = (100 - 0)/(2 - 0) = 50

<em>2 - 4 minutes</em>

Pat = (200 - 125)/(4 - 2) = 37.5

Cable = (200 - 100)/(4 - 2) = 50

<em>4 - 5 minutes</em>

Pat = (225 - 200)/(5 - 4) = 25

Cable = (250 - 200)/(5 - 4) = 50

So, the complete table is:

Time   0 - 2 minutes     2 - 4 minutes    4 - 5 minutes

Pat           62.5                     37.5                   25

Cable       50                         50                      50

<h3>Is the rate of change constant for Pat? Is it constant for the cable car? </h3>

The rate of change is not constant for Pat, while the rate of change is constant for the cable car

This is so because, we have different values for the rate of change for Pat, while we have only one value for the rate of change for Cable car

<h3>The average rate of change over the entire trip up the mountain</h3>

This is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

Pat = (250 - 0)/(6 - 0) = 41.7

Cable = (250 - 0)/(5 - 0) = 50

Hence, Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

Read more about average rate of change at

brainly.com/question/2170564

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