1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sammy [17]
3 years ago
5

Please help me with this problem.​

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0

Answer:

○ \displaystyle f(x + 1) = x^3 + 4x^2 + 3x + 1

Step-by-step explanation:

When shifting to the left, you use, in the form of \displaystyle x - c,\displaystyle x + 1,in which −c gives you the OPPOSITE terms of what they really are.

I am joyous to assist you anytime.

You might be interested in
Para encher 2/5 de uma piscina são necessários 60.000 litros de água. Qual é a capacidade dessa piscina?
natali 33 [55]

Answer:

A capacidade dessa piscina é de 150.000 litros de água.

Step-by-step explanation:

A capacidade da piscina é de x.

Para encher 2/5 de uma piscina são necessários 60.000 litros de água.

Isto implica que:

\frac{2x}{5} = 60000

2x = 60000*5

x = \frac{60000*5}{2}

x = 150000

A capacidade dessa piscina é de 150.000 litros de água.

8 0
2 years ago
A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 7% vinegar, and the second brand co
Lina20 [59]

Answer: There is 162 ml of first brand and 108 ml of second brand.

Step-by-step explanation:

Since we have given that

Percentage of vinegar that the first brand contains = 7%

Percentage of vinegar that the second brand contains = 12%

Percentage of vinegar in mixture = 9%

Total amount of dressing = 270 ml

We will use "Mixture and Allegation":

First brand                  Second brand

     7%                                12%

                       9%

--------------------------------------------------------

12%-9%             :                9%-7%

 3%                   :                    2%

So, ratio of first brand to second brand in a mixture is 3:2.

So, Amount of first brand she should use is given by

\dfrac{3}{5}\times 270\\\\=162\ ml

Amount of second brand she should use is given by

\dfrac{2}{5}\times 270\\\\=108\ ml

Hence, there is 162 ml of first brand and 108 ml of second brand.

4 0
3 years ago
Please help I'm confused. It's finding a function
shepuryov [24]
Easy, that is the slope from (2,f(2)) to (3,f(3))

remember that the slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

find f(2) and f(3)
f(2)=2²+6(2)+5=4+12+5=21
f(3)=3²+6(3)+5=9+18+5=32

so the slope from (2,21) to (3,32) is (32-21)/(3-2)=11/1=11

answer is 11
3 0
3 years ago
Joan is 4 feet 2 inches tall. There are 2.54 centimeters in 1 inch. What is Joan’s height in centimeters?
Montano1993 [528]

Answer:

Well its 127

Step-by-step explanation:

4 feet = 48 inches. 2.54 = 1 inch. SOOOOOOOOO. 2.54 x 48 + 2 = 127 :DD

3 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!<br> If f(x) = -(24 – 32) – x, find f(-2).
Rama09 [41]
There are 2 answers.
Hope it helps :)

7 0
2 years ago
Other questions:
  • A pens nearest 1/2 inch
    14·1 answer
  • A student solved the following problem and made an error. In which line did the student make the first mistake. Line A, Line 2,
    8·1 answer
  • What are the prime numbers of numbers 1-49?
    8·1 answer
  • I need the answer for all the 6 questions and I also need them to be explained please... Fast...
    14·1 answer
  • The answers to the 3 questions
    15·1 answer
  • Drag the tiles to the correct boxes to complete the pairs.
    6·1 answer
  • 3) Calculate the area of the entire triangle below. Show your work *<br><br> 22<br> 31<br> 8
    9·1 answer
  • What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
    13·2 answers
  • The question is in the picture. PLEASE HELP!!!! Thank you!!!;);)
    10·1 answer
  • Solve the system substitution y= 4x + 1 and 3x+2y =13
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!