Plss join really bored ID 852 183 4117 code WKJV5p

Mathematics

1 answer:

saul85 [17]2 years ago

3 0

Answer:

bet

Step-by-step explanation:

You might be interested in

75% of 7th graders are returning to school. If there are 300 7th graders returning to school, how many total 7th graders are the

bagirrra123 [75]

Answer:

there are 350 in all of the 7th grade

4 0

2 years ago

The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected

mr Goodwill [35]

We have that if we assume standard exponential growth, the equation of the population will be: $7000*e^{kt}$ if we start counting from the moment that the population was 7000. We are given that 7000* $e^{5k}$ =12000, namely that P(5)=12000 and we need to find $7000e^{(5+5)k}=7000e^{10k}$ . Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000 $\frac{12000^2}{7000^2}$ = 20571 people.

3 0

2 years ago

How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?

Mumz [18]

$\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0$

Step-by-step explanation:

$\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\ both\ parts\ of\ the\ equation\ by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5} (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K$

7 0

1 year ago

How to convert angle in radians to degrees?

jek_recluse [69]

360° = 2π
2 = 360° / π
1 rad = 360° / 2π

3 0

2 years ago

Sally was the waitress at two tables. At the first table the bill came to $38.70 and the tip was 15%. At the second table the bi

rewona [7]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{15\% of 38.70}}{\left( \cfrac{15}{100} \right)38.70}\implies \underline{5.805}~\hfill \stackrel{\textit{20\% of 33.45}}{\left( \cfrac{20}{100} \right)33.45}\implies \stackrel{\textit{larger}}{\underline{6.69}} \\\\\\ \stackrel{\textit{by how much?}}{6.69-5.805\implies 0.885}$

3 0

2 years ago