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Amiraneli [1.4K]
2 years ago
14

You are given a number. Do you know the number that is 1/5 as big? Need answer ASAP ❤️❤️❤️

Mathematics
1 answer:
posledela2 years ago
4 0

Answer:

Step-by-step explanation:

yes,      (given number) / 5

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Can somebody solve this for me please?
Karo-lina-s [1.5K]

Answer:

D

Step-by-step explanation:

3 0
2 years ago
Use slope formula to find the missing coordinate.<br><br> (r, 1) and (5, -7) Slope = 8/3
Lena [83]

Answer:

r=8

Step-by-step explanation:

The formula for slope is

m = (y2-y1)/ (x2-x1)

Substitute in what we know.

8/3 = (-7-1)/(5-r)

Simplify

8/3 = -8/(5-r)

We can use cross products to help us solve.

8 * (5-r) = 3 * (-8)

divide each side by 8

8/8 * (5-r) = 3 * (-8)/8

5-r = -3

Subtract 5 from each side

5-r-5 = -3-5

-r = -8

Multiply by -1

r = 8

3 0
2 years ago
Help me plz !!!!!!!!!!!!!!!!!
trapecia [35]

Answer:

the answer should be 54.6 grams

7 0
2 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
Factor the expression.<br> 3x2 + 7x-6
Sedbober [7]

Answer:

this answer is. _48 am I right

3 0
2 years ago
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