we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Option B is the odd one out
Answer:
I think It's option (B) 45
Step-by-step explanation:
But I am not sure It's correct or not
I hope It's helpful
Answer:
The correct answer is if you want no roots in the denominator, the correct answer is 
* ![\sqrt[3]{2y^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2y%5E%7B2%7D%20%7D)
Step-by-step explanation:
The mistake is that you can't take a cube root of a square at step 3 when 
is taken out.
