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2 years ago

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Asha bought 60 fruit baskets. 25% of the fruit baskets have 12 pieces of fruit in each basket. The remaining 75% of the baskets

have 15 pieces of fruits in each basket. Complete the model.

2 answers:

iren2701 [21]2 years ago

6 0

The complete model for the given question is;

Number of fruit baskets that contain 12 fruits = 15 baskets

Number of fruit baskets that contain 15 fruits = 45 baskets

We are told that he bought 60 fruit baskets.

Percentage of the fruit baskets that have 12 pieces of fruit = 25%

Percentage of the fruit baskets that have 15 pieces of fruit = 75%

Thus;

Number of fruit baskets that contain 12 pieces of fruit = 25% × 60 = 15 baskets

Number of fruit baskets that contain 15 pieces of fruit = 75% × 60 = 45 baskets

Read more about percentages at; brainly.com/question/11865045

Levart [38]2 years ago

5 0

Answer:

Number of baskets with 12 pieces of fruit: 15

Number of baskets with 15 pieces of fruit: 45

Step-by-step explanation:

25% x 60 = 0.25 x 60 = 15

75% x 60 = 0.75 x 60 = 45

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

The base edge of an oblique square pyramid is represented as x cm. If the height is 9cm, what is the volume of the pyramid in te

Tom [10]

A is correct:

Let volume v, length l, and h height.

v= (l²h)/3

v=(x²9)/3

v=3x²

5 0

3 years ago

Read 2 more answers

Evaluate the question?

Snezhnost [94]

Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)

3 0

2 years ago

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ABCD is a quadrilateral inscribed in a circle, as shown below:

german

Answer:

A. (x + 16) + (6x − 4) = 180

Step-by-step explanation:

Inscribed quadrilateral has opposite angles supplementary.

<u>So</u>

m∠A + m∠C = 180°

or

m∠B + m∠D = 180°.

<u>Since</u>

m∠A = x + 16,
m∠B = x,
m∠C = 6x - 4,
m∠D = 2x + 16

we can use either pair of angle measures to work out the value of x and then find the value of each angle.

<u>We can verify the first option is the only correct one.</u>

m∠A + m∠C = 180°
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3 years ago

A n =−1+3(n−1) an=−1+3(n−1) what is the 55 term in the sequence

Sindrei [870]

ANSWER

$a_{55}=161$

EXPLANATION

The general term for the sequence is

$a_n=-1+3(n-1)$

To find the 55th term, we have to substitute
$n = 55$
in to the general term and simplify.

This implies that,

$a_{55}=-1+3(55-1)$

$a_{55}=-1+3(54)$

$a_{55}=-1+162$

$a_{55}=161$

Therefore the 55th term is 161.

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2 years ago