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galben [10]
2 years ago
8

suppose that 17 inches of wire costs 51 cents. at the same rate, how much ( in cents ) will 33 inches of wire cost?

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
8 0

\bf \begin{array}{ccll} inches&cents\\ \cline{1-2} 17&51\\ 33&x \end{array}\implies \cfrac{17}{33}=\cfrac{51}{x}\implies 17x=33\cdot 51\implies x = \cfrac{33\cdot 51}{17} \\\\\\ x = 33\cdot \cfrac{51}{17}\implies x = 33\cdot 3\implies x = 99

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quester [9]
Use the box method.
5 0
3 years ago
Find the slope of (6,2) (8,4)
denis23 [38]

Answer:

2/2 = 1

Step-by-step explanation:

y2 - y1           4 - 2          2            Equals 1

x2 - x1           8 - 6          2

4 0
3 years ago
Answer Is not C<br>please help​
Katyanochek1 [597]

Answer:

B

Step-by-step explanation:

Well since it is arthimetic sequence we know the formula

We know d is difference between second term and first so it will be -5- (-12)= -5+12= 7

a_{n}= a _{1}+ d (n-1) \\a_{n}= -12+7(n-1)\\a_{n} = -12+7n-7\\a_{n}= 7n-19

the domain of this is 1,2,3,4.......

range is -12,-5,2,9.......

Therefore answer is B.

5 0
3 years ago
Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin
levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

  • 3\frac{3}{5}=\frac{18}{5} sq meters

Grandmother's wrapping paper:

  • 1\frac{1}{2}=\frac{3}{2} sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

                     =\frac{18}{5}+\frac{3}{2}

                     =\frac{36}{10}+\frac{15}{10}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

                      =\frac{36+15}{10}

                      =\frac{51}{10}

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0
2 years ago
The table below lists the masses and volumes of several pieces of the same type of metal. There is a proportional relationship b
galben [10]
In effect, there is a proportional relationship between the mass and the volume of the pieces of metal. The equation of the line that adapts to the given data is given by: y = 0.1174x. Therefore the proportionality constant is 0.1174
8 0
3 years ago
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