All categories

3 years ago

If 45 and 40 are the respectively median and mean of any data, then find its mode

1 answer:

5 0

The mode is 55

i found this by doing

3(45) - 2(40)
= 55

to find the mode when given just the median and mode always use the formula of 3(median) - 2(median) hope this helped!

You might be interested in

ivann1987 [24]

Answer:

AA SIMILARITY statement

SSS similarity statement is also possible.

Step-by-step explanation:

$In \: \triangle CBA \: and \: \triangle TVU \\ \angle B \cong \angle V... (given) \\\angle A \cong \angle U... (given) \\\therefore \triangle CBA \sim \triangle TVU... (By AA\: Postulate) \\$

5 0

4 years ago

I'll mark brainly for who ever answers

kirza4 [7]

Answer:

Step-by-step explanation:

Let the width be x, and the length be y

xy = 50

y = 2x

2x^2 = 50

x^2 = 25

x = 5

y = 10

3*8 = 24

7 0

3 years ago

Read 2 more answers

How do I make 2 3/4 into a decimal?

klasskru [66]

Well, 2 is a whole number so you keep that as a whole number. 3/4 is like money 4 quarters equals a dollar so how much is 3 quarters. So the answer is 2.75

8 0

4 years ago

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Line AB

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Line BC

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Line AC

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

Perimeter of Triangle ABC

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago

2.) Which expression has a value of -4? A. (-4) B. |-4| C. |4| D. -|4|

Liono4ka [1.6K]

Answer:

A and D both have a value of -4

Step-by-step explanation:

A. (-4) = -4

B. |-4| = positive value of what is inside = 4

C. |4| = positive value of what is inside = 4

D. -|4| = -positive value of what is inside = -4

5 0

3 years ago

Read 2 more answers