Answer:
Step-by-step explanation:
Probably the easiest way to set this up and solve it is to use proportions. We'll put miles on the top and gallons on the bottom:

Since we know the first unit rate of 32 miles per 1 gallon, we put those numbers where they belong in another fraction (ratio), with the number of miles on top with the "mi" and the number of gallons on bottom with the "gal":

Now we fill in what we know about the second ratio and leave the unknown to be solved for. We want to know how many gallons of gas, x, does he need to travel 500 miles. We put the 500 with the "mi" and the x for "gal":

and cross multiply to solve.
32x = 500 so
x = 15.6 or, to the nearest whole gallon, 16 gallons.
Answer= 375
angle 2 if 125 and I multiply 125 by 3 and got the 375
Answer:
Option (2)
Step-by-step explanation:
Domain of a function is represented by the set of x-values (Input values) and Range of the function is represented by the set of y-values (Output values)
From the graph attached,
Given function is,

Domain of this function will be {x ∈ R | x ≠ -2}
[Since, point x = -2 doesn't lie on the given graph]
Range of the function will be {y ∈ R | y ≠ -5}
Therefore, Option (2) will be the correct option.
Answer:
i wuv you
Step-by-step explanation:
The angles produced are vertically opposite angles, thus opposite angles are <u>congruent</u>. The applicable statements are; A, B, C and D.
Lines AD and EC meeting at point B produces set of angles that are <u>congruent</u> (by vertical opposite property).
Now considering the given diagram, it can be observed that the following statements <u>are</u> applicable: A, B, C and D.
- Option A is applicable because of the <em>rigid</em> transformation process of
rotation about B. - Option B is applicable because D will be <em>located</em> on ray BA after the
rotation.
- Option C is applicable since both processes <em>are</em> true.
- Option D is applicable since <ABC and <DBE are <em>vertically</em> opposite angles.
- Option E is NOT applicable <ABC is NOT <em>congruent</em> to <ABE.
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