Need help with this question

Mathematics

2 answers:

Nonamiya [84]3 years ago

7 0

It’s 450! Hope this helps be

geniusboy [140]3 years ago

6 0

Answer:

450

7,500 + 450

Step-by-step explanation:

You might be interested in

How do i make my grades go up quickly- yes in all subjects plz help me

sveticcg [70]

Answer:

Step-by-step explanation:

A way to make your grades go higher is by asking your teacher for extra credits. If you fail some quizzes ask your teacher to re-take it to get a better grade, another way is ask your teacher for assistance on assignments.

6 0

3 years ago

PLEASE HELP Will mark brainliest

ss7ja [257]

For the first one, the range is the largest number minus the smallest number. The largest number in this case is 11 and the smallest is 4. 11 - 4 = 7 so the maximum range is 7 inches.

For the second one, the IQR is Q3 - Q1. This means 30 - 20 = IQR and 30 - 20 is 10 books.

And the last one asks for dinner customers, and there are 54 total. 28 of them chose cheesecake as their favorite dessert. This means that the amount of dinner customers that chose cheesecake as their favorite is 28/54 or 0.5185, whihc is 51.85%

Hope this helps!!

6 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$