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svetoff [14.1K]

3 years ago

10

The amount of money that high school students spend on fast food each month is usually between $50 and $200. However, there are

a few students who do not eat fast food at all. What measure of spread would be the most appropriate to measure the amount of money that high school students spend on fast food per month?

2 answers:

Alex17521 [72]3 years ago

7 0

Answer: B

Step-by-step explanation:

trasher [3.6K]3 years ago

3 0

Answer:

mean

Step-by-step explanation:

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Find the solutions to x⁴-64=0 and the x-intercepts of the graph of y=x⁴-64.

Setler [38]

Answer:

1. $x_1=2\sqrt{2}\\x_2=-2\sqrt{2}\\x_3=i2\sqrt{2}\\x_4=-i2\sqrt{2}$

2. $A=(2\sqrt{2},0)$ and $B=(-2\sqrt{2},0)$

Step-by-step explanation:

We have the expression $x^4-64=0$ to find the solutions we have to clear $x$ . Then,

$x^4-64=0$ Add 64 in both sides of the equation.

$x^4-64+64=64\\x^4=64$

Now we have to re-write the equation:

$u=x^2$ ⇒ $u^2=(x^2)^2\\u^2=x^4$

Then,

$u^2=64$

Apply square root on both members

$\sqrt{u^2}=\sqrt{64}\\u=8 , u=-8$

Now substitute back $u=x^2$

1. $x^2=8$

2. $x^2=-8$

Solving for x:

1. $x=+\sqrt{8}=\sqrt{2^3}=\sqrt{2^2}.\sqrt{2}\\x=2\sqrt{2}\\or\\x=-\sqrt{8}\\x=-2\sqrt{2}$

2. $x=+\sqrt{-8}=\sqrt{(-1).8} =\sqrt{-1}\sqrt{8} \\x=i\sqrt{8}\\x=i.2\sqrt{2} \\or\\x=-\sqrt{-8}\\x=-i.2\sqrt{2}$

Then the solutions for $x^4-64=0$ are:

$x_1=2\sqrt{2}\\x_2=-2\sqrt{2}\\x_3=i2\sqrt{2}\\x_4=-i2\sqrt{2}$

To find the x intercepts of the graph $y=x^4-64$ we have to replace with y=0.

This means: $x^4-64=0$

We already found the solutions for the expression, but we have to consider only the real solutions.

$x_1=2\sqrt{2}\\x_2=-2\sqrt{2}$

Because in a graph we can't have imaginary solutions.

Then the x intercepts of the graph are:

$A=(2\sqrt{2},0)$ and $B=(-2\sqrt{2},0)$

The graph of the function is:

3 0

3 years ago

(2sin60°)(3tan60°)—(4tan45°)(2cos45°)

Dimas [21]

Answer:

$9 - 4\sqrt{2}$

Step-by-step explanation:

sin60° = $\frac{\sqrt{3} }{2}$

tan60° = $\sqrt{3}$

tan45° = 1

cos45° = $\frac{1}{\sqrt{2} }$

(2sin60°)(3tan60°) - (4tan45°)(2cos45°)

now substitute the values of each trigonometrical angles

$(2*\frac{\sqrt{3} }{2} )(3*\sqrt{3} ) - (4*1)(2*\frac{1}{\sqrt{2} } )$

$\sqrt{3} * (3\sqrt{3}) - 4*(\frac{2}{\sqrt{2} } )$

$3*3 - 4*\frac{2}{\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} }$

$9 - 4 *\frac{2\sqrt{2} }{2}$

$9 - 4 * \sqrt{2}$

$9 - 4\sqrt{2}$

5 0

3 years ago

30 POINTS AND BRAINLIST FOR RIGHT ANSWER

alukav5142 [94]

Answer:

59°

Explanation:

If you add the angles 99° from angle C in the top shape and add 22° on the bottom shape it will give you 121°. When you get this subtract it from 180°

180°-121°= 59°

So, it's 58°

You can check by adding 180°+121°+59° = 180°

6 0

3 years ago

I need help draw a array to represent the problem 5 x 8

xz_007 [3.2K]

Well draw a box with 10 squares going up and 20 square is going sideways and then shade and 5/8 of it

4 0

3 years ago

How do you multiply 342 and 13.5

Kaylis [27]

Answer:

Step-by-step explanation: first multiply 342 and 135

then put the decimal just before the ones digit.

answer is

4617.0

please mark as brainliest

4 0

3 years ago