This would be 2c^3 Answer
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The two cases are :
or
- a -4 = 0, that leads to a = 4
We can conclude :
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
</span>
Answer:
7 & 13
Step-by-step explanation:
Let the first number be x
2nd number = 8 less than 3 times the other
2nd number = 3x - 8
Their sum = 20
X + 3x - 8 = 20
4x -8 = 20
Collect like terms
4x = 20+8
4x = 28
Divide both sides by 4
4x/4 = 28/4
X = 7
First number = 7
2nd number = 3x - 8
= 3(7) - 8
= 21 -8
= 13.
Therefore the numbers are 7 and 13
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