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12345 [234]
3 years ago
9

The temperature of a point $(x,y)$ in the plane is given by the expression $x^2 + y^2 - 4x + 2y$. what is the temperature of the

coldest point in the plane?
Mathematics
1 answer:
ollegr [7]3 years ago
3 0
x^{2} + y^{2}-4x+2y

can be written as follows:

x^{2} -4x+ y^{2}+2y

(x^{2} -4x+4)-4+ (y^{2}+2y+1)-1

(x-2)^{2}+(y+1)^{2} -5

since (x-2)^{2} and (y+1)^{2} are always positive, except for x=2 and y=-1, when they become 0,

the minimum value of this expression is when x=2, and y=-1, that is -5



Answer: -5
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Answer:

$420t

Step-by-step explanation:

Given data

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3 years ago
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Answer:

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3 years ago
THANK YOU (PLEASE HELP) &lt;3 C: TYSMMMM PLZZZ Write an equation of a parabola that is wider than the parent function, reflects
My name is Ann [436]

Answer:

y=-2x^2-4

Step-by-step explanation:

The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.

y = 2x^2

Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.

Final Equation: y=-2x^2-4

3 0
2 years ago
A) 2-x,when x=5
MrRissso [65]

Answer:

a) 2-5 = -3

b) 3(4) + 2(4) = 20

c) (3(5)+2)(5-4) = 17

Step-by-step explanation:

Substitute the variables for their values and then solve from there. Hopefully this helps, I don't know if I answered your question fully.

7 0
2 years ago
Read 2 more answers
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