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Lerok [7]
3 years ago
10

5 less than 3 times a number is 7. Write an equation.

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0
3n-5=7


The three times a number goes first because there is the “less than” phrase.
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consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).
Mila [183]
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
4 0
3 years ago
2x+3y=9xy is this a linear or non-linear function pls give steps if posible​
liq [111]

Answer:

Step-by-step explanation:

To Differentiate A linear Function from a non-linear one we have Several rules.

1: check the Variables exponent degree of the function if the exponent is zero or 1 of the function that's the function is linear.

2: if it's not 0 or 1 and Greater than 1 than it's non linear function also if the exponent is of any negative value like -1 or -2 than it's also a non linear function. The Given function is a non linear function because the 9xy value has two variables multiplied if we add the exponent values together which are 1+1 = 2 hence proved it's a non linear function. One More Thing a graph of non linear function will be always other than that of a straight line.

7 0
3 years ago
Help me please solves this my math teacher will yell at me if I don’t get this done!!!
VARVARA [1.3K]
The answer is 75

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5 0
4 years ago
How is 6/10 written as a decimal?
BARSIC [14]
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6 0
3 years ago
Read 2 more answers
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

5 0
3 years ago
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