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harkovskaia [24]
3 years ago
13

a company donates 935 pencils to a school. the pencils are divided evenly among 9 classrooms. the rest of the pencils are given

to the library. how many pencils were doamated to the donated to the school and to tje library?
Mathematics
2 answers:
wariber [46]3 years ago
8 0
The problem deals with a division and the rest of it, that is dividing the total amount of pencils into 9 classrooms and the rest, lets express it as fraction:
935/9 = 103 + 8/9
that is, if we multiply 103*9 we get 927 and are 8 pencils left over, therefore, 8 pencils are donated to the library and each classroom gets 103 pencils, in total 935 pencils are donated.
Contact [7]3 years ago
4 0
Divide 935 by 9, which is 103 R8. The remainder is how many pencils were donated to the library. So, 103 pencils were donated to the school and 8 pencils were donated to the library.
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8 0
3 years ago
Read 2 more answers
A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s
Artemon [7]

Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

6 0
3 years ago
An angle's complement is 35°. Find the measure of its supplement. A) 55° B) 65° C) 125° D) 155° E) 180°
kenny6666 [7]

Answer:

C) 125°

Step-by-step explanation:

Supplementary angles add to 180 degrees.  Complementary angles add to 90

An angle's complement is 35°.

35+x =90

Subtract 35 from each side

35 -35+x = 90-35

x = 55

We want to find the supplement of this angle

55+y = 180

Subtract 55 from each side

55-55+y = 180-55

y= 125

The angle is 55 so its supplement is 125

7 0
3 years ago
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