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viktelen [127]
2 years ago
5

9. If a train travels 270 mi. in 9 hr., what is its average speed?

Mathematics
2 answers:
Aleks [24]2 years ago
5 0

Answer:

30 miles per hour

Step-by-step explanation:

You divide the distance by time to receive the average speed.

270 / 9 = 30

RoseWind [281]2 years ago
5 0

Answer:

The train travels 30 miles in 1 hour

Step-by-step explanation:

First, you take the miles and divided it by the hours. That will give you the average speed/MPH (miles per hour)

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1/3 is the answer to this question
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a motorboat travels 371 kilometers in 7 hours going upstream. it travels 525 kilometers going downstream in the same amount of t
e-lub [12.9K]

Answer:

Speed of boat in still water = 64 km/hr

Speed of the current = 11 km/hr

Step-by-step explanation:

Let the speed of motorboat in still water = x km/hr

Let the speed of current = y km/hr

Motorboat travels 371 km in 7 hours going upstream.

Speed of motorboat while going upstream = speed of motorboat in still water - speed of current = (x-y)

=> \[x-y = \frac{371}{7}\]

=> \[x-y = 53\] ------------------------------(1)

Motorboat travels 525 km in 7 hours going downstream.

Speed of motorboat while going downstream = speed of motorboat in still water + speed of current = (x+y)

=> \[x+y = \frac{525}{7}\]

=> \[x+y = 75\] -----------------------------(2)

Solving for x and y from (1) and (2):

Adding (1) and (2):

2x = 128

=> x = 64

Substituting the value of x in (1), y = 11

6 0
3 years ago
Juan needs to rewrite this difference as one expression. First he factored the denominators. What step should Juan take next whe
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The next step Juan will take is to multiply the second fraction by (x-2)/(x-2).

Given that Juan needs to rewrite this difference as one expression (3x/(x²-7x+10))-(2x/(3x-15)) and factor the denominator as (3x/(x-2)(x-5))-(2x/3(x-5)).

An algebraic expression in mathematics is an expression composed of variables and constants and algebraic operations (addition, subtraction, etc.). Expressions are made up of concepts.

The given expression is (3x/(x²-7x+10))-(2x/(3x-15))

Firstly, we will factored the denominator as

(3x/(x-2)(x-5))-(2x/3(x-5)).

Now, we will multiply and divide the second fraction by (x-2), we get

(3x/(x-2)(x-5))-((2x(x-2))/3(x-5)(x-2)).

Hence, the next step when subtracting these expressions (3x/(x-2)(x-5))-(2x/3(x-5)) is multiply the second fraction by (x-2)/(x-2).

Learn more about algebraic expression from here brainly.com/question/4344214

#SPJ4

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Using the Pythagorean theorem:

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