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2 years ago

Which of the following is a reason people sometimes use mean or median to misrepresent the “average” of a set of data?

2 answers:

8 0

The answer to this question is option D(In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda

ki77a [65]2 years ago

8 0

Answer: In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda.

Step-by-step explanation:

We know that the "mean" is the "average" we used where we need to add up all the numbers and then divide by the number of elements where as the "median" is the "middle" value in the list of numbers.

The mean and median would not affected by outlying data points within data sets. Thus, the median is often used when a data set has outlying data points that could influence the mean and thereby misrepresent the middle of the data set.

The correct reason people sometimes use mean or median to misrepresent the “average” of a set of data is " In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda. '

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3 years ago

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2 years ago

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Arrange the following numbers in increasing order: \begin{align*} A &= \frac{2^{1/2}}{4^{1/6}}\\ B &= \sqrt[12]{128}\vph

prisoha [69]

Answer:

The order is "D, B, A, E, C".

Step-by-step explanation:

The numbers are as follows:

$A=\frac{2^{1/2}}{4^{1/6}}\\\\B = \sqrt[12]{128}\\\\C=(\frac{1}{8^{1/5}})^{2}\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}$

Simplify the value of A, B, C, D and E as follows:

$A=\frac{2^{1/2}}{4^{1/6}}=\frac{2^{1/2}}{2^{2/6}}=\frac{2^{1/2}}{2^{1/3}}=2^{1/2-1/3}=2^{1/6}=1.1225\\\\B = \sqrt[12]{128}=(128)^{1/12}=(2^{7})^{1/12}=2^{7/12}=1.4983\\\\C=(\frac{1}{8^{1/5}})^{2}=(\frac{1}{(2^{3})^{1/5}})^{2}=(\frac{1}{2^{3/5}})^{2}=\frac{1}{2^{3/5\times2}}=\frac{1}{2^{6/5}}=2^{-6/5}=0.4353\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}=\sqrt{\frac{2^{-2}}{2^{-1}\cdot 2^{-3}}}=\sqrt{2^{-2+1+3}}=2\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}= (2^{1/2})^{1/3}\cdot 2^{-2/4}=2^{-1/3}=0.7937$

Arrange the following numbers in increasing order as follows:

D > B > A > E > C

Thus, the order is "D, B, A, E, C".

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2 years ago