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Natalija [7]
3 years ago
7

Which of the following is a reason people sometimes use mean or median to misrepresent the “average” of a set of data?

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0
The answer to this question is option D(<span>In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda</span>
ki77a [65]3 years ago
8 0

Answer: In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda.

Step-by-step explanation:

We know that the "mean" is the "average" we used where we need to add up all the numbers and then divide by the number of elements where as the "median" is the "middle" value in the list of numbers.

The mean and median would not affected by outlying data points within data sets. Thus, the median is often used when a data set has outlying data points that could influence the mean and thereby misrepresent the middle of the data set.

The correct reason people sometimes use mean or median to misrepresent the “average” of a set of data is " In data sets with outliers, either the mean or median can be used to make the data set appear more favorable to their agenda. '

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During a business trip, an individual stopped at two rest stops. In the parking lot of the first rest stop, they counted 20 cars
olganol [36]

Answer

given,

on first stop

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on second stop

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we need to calculate which rest stop has higher ratio of car to truck.

Rest Stop 1

ratio= r₁ =\dfrac{cars}{trucks}

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Rest Stop 2

ratio= r₂ =\dfrac{cars}{trucks}

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hence, r₂ > r₁

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3 0
3 years ago
3 10/15 - 1 12/15 what is difference
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Read 2 more answers
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