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Anna007 [38]
3 years ago
9

Please help me with this geometry question image attached

Mathematics
2 answers:
shutvik [7]3 years ago
3 0

Answer:c

Step-by-step explanation:

svlad2 [7]3 years ago
3 0

3m. The wall of the building is 3m far from the base of the ladder.

The key to solve this problem is use trigonometric ratios.

The cosine of the angle is the adjacent leg divided by the hypotenuse.

From the image attached we can modeling the problem as a right triangle, where we can see that the adjacent leg is the unknown, hypotenuse is 6m (long of the ladder), and the ladder make an angle of 60°  leans againts the building's wall, and x is the long of the adjacent leg. To calculate how far is the base of the ladder from the wall:

Cos 60° = adjacent leg/hypotenuse

adjacent leg = cos 60° x hypotenuse

x = cos 60° (6m) = (0.5)(6m) = 3m

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8 0
4 years ago
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Semmy [17]

Answer:

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7 0
3 years ago
In triangle ABC, angle A is 75o and angle B is 20o. Select the triangle that is similar to triangle ABC.
Arturiano [62]

Answer:

A. \triangleDEF where \angle D = 75^{\circ} and \angle E = 20^{\circ}.

Step-by-step explanation:

At first we must keep in mind that two triangles are similar when they have same angle configuration, that is, each pair of angles is congruent. If \triangleABC and \triangleDEF, then \angle A \equiv \angle D and \angle B \equiv \angle E. Hence, \angle D = 75^{\circ} and \angle E = 20^{\circ}.

In a nutshell, correct answer is A.

4 0
3 years ago
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The
Ivan

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Step-by-step explanation:

6 0
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