Am I correct on #6???
1 answer:
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Answer:
Option A and C have rotational symmetry.
Step-by-step explanation:
The graph of odd functions have rotational symmetry about its origin.
Here the first graph is a graph of f(x)= which is an odd function bearing an exponent of 3.
A function is "odd" when we plug in any negative value in then it gives negative of
.
And we also know that when a graph is mirroring about the y-axis then it is an even functions.
For even functions we have reflection symmetry rather than rotational symmetry.
The second graph is a graph of which is an even function as we can see that its graph is mirroring about the y-axis.
The third graph is a graph of an ellipse which is possessing rotational symmetry.
The order of symmetry of an ellipse is generally 2.
Order of symmetry:
The order of rotational symmetry of an object is how many times that object is rotated and fits on to itself during a full rotation of 360 degrees.
So graph A and C have rotational symmetry.