5.250
To change a fraction to a decimal fraction divide the numerator by the denominator.
that is 21 ÷ 4 = 5.250 ( to 3 decimal places )
An expression is defined as a set of numbers, variables, and mathematical operations. The value of x for which the expression (x-1)(x-7)=0 is 1 and 7.
<h3>What is an Expression?</h3>
In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
For the given expression, (x-1)(x-7), the value of x for which the expression will be equal to 0 can be found by equation the factors of the expression to 0. Therefore,
x-1 = 0
x = 1
and
x-7=0
x = 7
Hence, the value of x for which the expression (x-1)(x-7)=0 is 1 and 7.
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Answer:
42x -27
Step-by-step explanation:
we apply distributive property:
7(6x – 4) + 1
7*6x - 7*4 +1
42x - 28 +1
42x -27
Like terms are those terms, which have the common variable with same powers.
The number of like terms in the given expression are 3, which is
. the option 3 is the correct option.
<h3>What is like terms?</h3>
In the algebra or the algebraic expression the like terms are those terms, which have the common variable with same powers.
Given information-
The given expression in the problem is,

The given expression is the algebraic expression which 3 number of unknowns variables.
There is total 6 terms in the given expression. In which 5 terms consists the variables and one term is constant.
In the given expression,
- The total number of terms with variable x are 3 which are,
.
- The total number of terms with variable y is 2 which is
.
- The total number of terms with variable z is 1 which is
.
- The total number of constant terms is 1 which is 7.
Thus the number of like terms in the given expression are 3, which is
. the option 3 is the correct option.
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The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P,
, where
. The slope of the secant line through P and Q is given by the difference quotient,

where we are allowed to simplify because
.
Then the equation of the secant line is

Taking the limit as
, we have

so the slope of the line tangent to the curve at P as slope 2.
- - -
We can verify this with differentiation. Taking the derivative, we get

and at
, we get a slope of
, as expected.