C=5(f-32)/9 make f the subject

<img src="https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B4%20%20%7D%20%20%20%5Ctimes%20%20%7Ba%7D%5E%7B5%7D%20" id="TexFormula1" title=

tekilochka [14]

The answer would be a^9 (a to the ninth power) because you would add the exponents.

5 0

3 years ago

The area of a cross section perpendicular to the base of a rectangular prism is 45 square inches. If the length and width of the

iren2701 [21]

Check the picture below.

pretty sure you know how much that is.

7 0

3 years ago

Read 2 more answers

when a card is drawn from a standard deck of 52 cards, what is the probability of getting a. queen b.a red. c.a queen or a red c

Brut [27]

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

Solution:

Given that card is drawn from a standard deck of 52 cards.

Need to determine probability of getting

(a) queen (b) red (c) a queen or a red card

$\text { Probability of an event }=\frac{\text { favorable number of events }}{\text { total number of events }}$

(a) Calculating probability of getting a queen from a deck of 52 cards

Favorable events are getting a queen of spade, heart , diamond or club.

Means number of favorable events = 4

Total events is all possible outcomes from 52 cards

So Total number of event = 52

$\Rightarrow \text { probability of getting a queen }=\frac{4}{52}=\frac{1}{13}$

(b) Calculating probability of getting a red card from a deck of 52 cards

Number of red cards are 13 cards of diamonds and 13 cards of heart = 13+13 =26

So number of favorable event = 26

Total number of event = 52

$\Rightarrow \text { probability of getting a red card }=\frac{26}{52}=\frac{1}{2}$

(c) Calculating probability of getting a queen or red card from a deck of 52 cards

Favorable events are 26 red cards + two queens of spade and club. Need to keep in mind that queens of heart and diamond is already considered in 26 red cards.

So number of favorable event = (26+2) = 28

Total number of event = 52

$\text { Probability of getting a queen or red card }=\frac{28}{52}=\frac{7}{13}$

Summarizing the result :

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

7 0

4 years ago

13. Represent (–6)3 using repeated multiplication. Best answer gets brainliest! 20 points!

mestny [16]

Answer:

-6 x -6 x -6

Step-by-step explanation:

because 6^3 is 6x6x6

5 0

4 years ago

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joe and Eric have to ship 75 packages. Joe can do the job alone in 5 hours. if Eric helps, they get it done in 4 hours. How long

marishachu [46]

Eric took 20 hours to do the job alone.

Step-by-step explanation:

Given :

Total work = 75 packages
Joe took 5 hours to complete the total work.

The amount of work Joe alone can do per hour = 75/5 = 15 packages.

The amount of work Joe and Eric together do per hour = 75/4 = 18.75

The amount of work Eric alone can do per hour = 18.75 - 15 = 3.75

The time Eric took to complete the entire work = 75 / 3.75 = 20 hours.

4 0

3 years ago