(2x + I) (2x-I) = 4x^2 + 1
Using the complex arithmetic rule:
(A + bi)(a-bi) = a^2 + b^2
A would be the 2x and b would be the i
So you would have:
(2x)^2 + (i)^2
(2x)^2 = 2x times 2x = 4x^2
i ^2 = 1
Final answer is 4x^2 + 1
Answer:
Step-by-step explanation:
• AB, BC, and AC form a triangle. Enter a possible value of AC....
So it asks for only a possible value of AC as there are many possible values.
Given AB = 8 cm and BC = 6 cm, they are in the ratio of 3:4.
Line segments of 3, 4 and 5 length will form a right-angled triange.
A possible value of AC = 5*2 = 10cm
• Points A, B, and C lie on the same line, and C lies between A and B.
So AC+CB = AB
AC+6 = 8
AC = 2cm
Enter this value of AC in the second
response box.
Answer:
9 4/5
Step-by-step explanation:
I belive you meant 49/5 where the correct answer would be 9 4/5
If the dimensions were all the same number ... the box was a cube ...
then each dimension would be (the cube root of 13,800) cm.
∛13,800 = 23.986... (rounded)
so the place to look is around 23 .
(22 x 23 x 24) = 12,144 <== too small; go up one integer
(23 x 24 x 25) = 13,800 <== Eureka !
The consecutive integers are 23, 24, and 25 .
