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Eddi Din [679]
3 years ago
10

What side lengths should be used to model a rectangle

Mathematics
2 answers:
zloy xaker [14]3 years ago
6 0

Answer:

B. x-2 and x+5

Step-by-step explanation:

Assoli18 [71]3 years ago
5 0
Hi how you doing today I did not get it but I tried
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for a group experiment, your science class measured the fine-particulate concentration in the air at random places around campus
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Will award Brainlyest!!! Choose the equation that represents a line that passes through points (−3, 2) and (2, 1).
Pachacha [2.7K]

Answer:2. Rate of change, or slope, is the change in y over change in x. Remember that a point is given in (x, y). Also that you need two points to find the change.

If you have two points, (x1, y1) and (x2, y2), the rate of change or slope

In your problem, the given points are (0, -1) and (2, -11)

The "initial value" is the y-intercept - where the graph intersects the y-axis and also where x = 0. The given point (0, -1) has x = 0, so the initial value is -1.

4. Remember the model equation for a graph of a line is

y = mx + b,

where m is slope and b is y-intercept - where the graph intersects the y-axis and also where x = 0.

The x-axis of the graph would be number of weeks, since it is independent.

The y-axis of the graph would be how much money she has.

Since she starts (at 0 weeks) at $25, the first point would be (0, 25). Notice here that it is the y-intercept since x = 0. The value of b in the model equation of a line y = mx + b would be 25.

The rate of change, or slope, is $5/week. This is m in the model equation of a line y = mx + b.

Putting b = 25 and m = 5 into the model equation y = mx + b (remember we use this equation because it works for all lines), the equation would be

y = 5x + 25.

4.

The slope of this will be -0.5degrees/hr, or just -0.5 if it is used as m in the 

y = mx+b equation. The slope is negative because it "decreases".

5. 

Plot each point and connect the dots. Remember the first number corresponds to the x-axis and the second to the y-axis.

For example in the table for x = -2 and y = -6, the point is (-2, -6), and from the origin (0,0) you go left 2 on the x-axis and down 6 to plot the point.

9.

I think you can do this if you can do #3, but now you have to find b by plugging in given values.

y = mx + b

y = 1212x + b

We can plug in the given point (3,1) to find b.

1 = 1212(3) + b

b = -3625

y = 1212 - 3625

10. Don't know which function you are referring to.

The slope is $10/week, or m = 10.

A point is (4, 90) because "After 4 weeks, Roberta has $90."

The y-intercept is 50 because x (weeks) = 0 at that time.

y = mx + b

y = 10x + 50

8 0
3 years ago
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Analyze relationships: The area of the shaded triangle is 5x^2 + 3x - 4. What is the area of the entire figure?​
blagie [28]

well, we know the shaded region has an area of 5x²+3x-4, there are three more sections of equal shape, so their areas must also be equal, meaning there are four regions of the same area of 5x²+3x-4, thus 4(5x²+3x-4) = 20x²+12x-16.

4 0
4 years ago
Can someone help with this to?
Gala2k [10]

Answer:

6 x

Step-by-step explanation:

because 1 times 6 then 2 then 3 and so on

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3 years ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
charle [14.2K]

Answer: t = - 5 ∈ I_{1} = ( -∞ , -4 )

Step-by-step explanation:

The standard form of O.D.E is written as :

y^{1} + p(t) = g(t)

Equation given :

(16-t^{2} )y^{1} + 9ty = 5t^{2} ,       y(-5) = 1

The first thing to do is to write the O.D.E in standard form , that is we will divide through by 16 - t^{2} , so we have

y^{1} + \frac{9ty}{16-t^{2}}=\frac{5t^{2}}{16-t^{2}}

With this , we can see that p(t) and g(t) are both continuous in the same domain. Therefore , the intervals are :

I_{1} = ( -∞ , -4 )

I_{2} = ( - 4 , 4 )

I_{3} = ( 4 , -∞ )

recall that y(−5) = 1 , then t = -5

This means that :

t = - 5 ∈ I_{1} = ( -∞ , -4 )

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4 years ago
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