6x^3y^9/36x^3y^-2 The x^3 values cancel each other out leaving the 1/6
(1/6)y^9/(y^-2) the y^-2 causes the y^9 to turn into y^11 (9+2=11)
(1/6)y^11/1 the 1/6 is multiplied by y^11
y^11/6

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.
Start by solving for x in the first problem:
3x=3+9y
x=1+3y
Then plug that into the second equation:
6(1+3y)-3y=-24
6+18y-3y=-24
15y=-30
y=-2
Then plug that back into first equation:
3x-9(-2)=3
3x+18=3
3x=-15
x=-5
Then I would check your answer by plugging those into both equations:
3(-5)-9(-2)=3
-15+18=3
3=3 CHECK
6(-5)-3(-2)=-24
-30+6=-24
-24=-24 CHECK
So the answer is x=-5 y=-2
The perfect square are the squares of the whole number 1,4,9,16,25,36,49,64,81,100 here are the square roots of all the perfect from i to 100 1. estimate first get as close as you can by finding two perfect square roots your number is between