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Debora [2.8K]
3 years ago
7

PLEASE HELP!!

Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

First blank: [-π/2 , π/2]

Second blank: [-π/2 , π/2]

Step-by-step explanation:

The conditions for inverse function to exist is that the function should be one to one function.

A function for which every element of the range of the function corresponds to exactly one element of the domain.

The function can be tested by the vertical line test.

For the given function f(x) = sin x is not one to one function.

so, the domain of the function f(x)=sin x restricted so that its inverse function exists

The domain will be the range provided that when we apply the vertical line test will intersects at only one point

So, the domain will be<u> [-π/2 , π/2]</u>

And this means f(x) = sin⁻¹ x are on the interval<u> [-π/2 , π/2]</u>

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Angle 1 is congruent to angles 3, 5, and/or 7

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Angles 1 and 3, 2 and 4, 5 and 7, and angles 6 and 8 are congruent because they are vertical angles. They have the same vertex. Not all of these are congruent to each other if this doesn’t make sense. It’s only 1 is congruent to 3, 2 congruent to 4, etc.

Then you have your corresponding angles. These are ones like angles 2 and 6, then 1 and 5. You can also have 8 and 4, or 7 and 3 as corresponding angles

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3 years ago
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