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3 years ago

9

Clark left for school at 7:43 a.m. he got to school 30 minutes late what time did Clark get to school

1 answer:

lilavasa [31]3 years ago

5 0

If clark left at 7:43, and 30 minutes later he arrived he would get to school around 8:13, 7:43 + 30 = 8:13

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52÷2= ?? find the quotient and remainder

vodomira [7]

52/2= 26

The quotient is 26, but there are no remainder.

Hope this helps!

7 0

3 years ago

Read 2 more answers

The expression (8-3)^2-(5-2)^2 is equivalent to what numerical expression

Tresset [83]

(8-3)²-(5-2)²
Follow the PEMDAS
P-Parenthesis
E-Exponents
M/D-Multiplication/Division
A/S-Addition/Subtraction
clear the numerals in the parenthesis:
(5)²-(3)²
Now do the exponents:
=25-9
=16
Its just: (5)²-(3)²

7 0

3 years ago

Please answer soon ty!

Hunter-Best [27]

Answer:

A

Step-by-step explanation:

4.22

8 0

3 years ago

One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P( $\text{B}_1$ ) = 0.2, P( $\text{B}_2$ ) = 0.4, P( $\text{B}_3$ ) = 0.3, P( $\text{B}_4$ ) = 0.6, P( $\text{B}_5$ ) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= $1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]$

P(A) = $1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]$

P(A) = $1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)$

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

4 0

4 years ago

A rectangular tank with a base 4 feet by 5 feet and a height of 4 feet is full of water. The water weighs 62.4 pounds per cubic

posledela

Answer:

(a) 13536.10J

(b) 27072.20J

Step-by-step explanation:

(a) Height of tank (h) = 4 feet = 4/3.2808 = 1.22m

Volume of water in full tank = 4ft×5ft×4ft = 80ft^3

Volume of water in half tank = 1/2 × 80ft^3 = 40ft^3

Density of water = 62.4lb/ft^3

Mass of water = density × volume = 62.4 × 40 = 2496lb = 2496×0.45359kg = 1132.16kg

Work done to empty half of the tank = mgh = 1132.16×9.8×1.22 = 13536.10J

(b) Work done to empty all of the tank = 2 × work done to empty half of the tank= 2 × 13536.10J = 27072.20J

4 0

3 years ago