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julia-pushkina [17]
2 years ago
5

I'll give brainliest

Mathematics
2 answers:
Evgen [1.6K]2 years ago
6 0

Answer:

104 feet i think

Step-by-step explanation:

andre [41]2 years ago
3 0

Answer:

C=√4^2+100^2=100.08

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What is the solution set to the equation 4x2 – 16 = 0?
Luda [366]

Answer:

2

Step-by-step explanation:

add 16 to zero

4x2=16

Divide 4x by 2 and 16 by two

4x=8

divide 8 by 4

x=2

4 0
3 years ago
Read 2 more answers
If y is proportional to the sqaure root of x and y equal x when x equal 5,evaluate y when x eqaul 9.​
Law Incorporation [45]

Answer:

y = 3\, \sqrt{5} when x = 9.

Step-by-step explanation:

The question states that y is proportional to \sqrt{x}. In other words, there is a constant a (a \ne 0) such that y = a\, \sqrt{x} for all x \ge 0.

The question also states that y = x when x = 5. Make use of this equality to find the value of a.

Since x = 5 and y = x, it must be true that y = 5. Substitute x = 5\! and y = 5\! into the equation y = a\, \sqrt{x} and solve for a:

5 = a\, \sqrt{5}.

\begin{aligned}a &= \frac{5}{\sqrt{5}} \\ &= \sqrt{5}\end{aligned}.

Thus, y = \sqrt{5}\, (\sqrt{x}) for all x \ge 0.

Substitute in the value x = 9 to find the corresponding value of y:

\begin{aligned} y &= \sqrt{5} \, (\sqrt{9}) \\ &= \sqrt{5} \times 3 \\ &= 3\, \sqrt{5}\end{aligned}.

6 0
2 years ago
What is straight is part of a line and has 2 endpoints
Yuri [45]
Answer:  Length

Explanation:

<span>straight line with 2 endpoints ====> Length</span>
3 0
3 years ago
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Please help! I can't figure this out
trasher [3.6K]

Answer:

see explanation

Step-by-step explanation:

(1)

CD = CE - DE = 8 - 2 = 6

CB = CD = 6 ( given as congruent ) , thus

AC = AB + CB = 4 + 6 = 10

(2)

∠ 2 + ∠ BCD + ∠ DCF  = 180° ( sum of angles on a straight line )

∠ 2 + 60° + 70° = 180°

∠ 2 + 130° = 180° ( subtract 130° from both sides )

∠ 2 = 50°

6 0
3 years ago
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Which order from least to greatest of 2.8, 2.8x10², 2.8x10⁻3, 2.8x10⁴, 2.8x10⁻5
Dominik [7]
2.8x10^-5 ; 2.8x10^-3 ; 2.8 ; 2.8x10^2 ; 2.8x10^4
7 0
3 years ago
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