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faltersainse [42]
3 years ago
15

An adiabatic capillary tube is used in some refrigeration systems to drop the pressure of the refrigerant from the condenser lev

el to the evaporator level. The R-134a enters the capillary tube as a saturated liquid at 50°C, and leaves at -12°C. Determine the quality of the refrigerant at the inlet of the evaporator.

Computers and Technology
1 answer:
kap26 [50]3 years ago
8 0

Answer:

The quality of refrigerant is 0.423

Explanation:

  • Adiabatic tubes drop the pressure from condenser level to evaporator level in refrigeration systems.
  • The values taken in this problem are from the saturated R-134a table.
  • All the calculation is attached in the image. In the problem, hf stands for the enthalpy of saturated liquid while hfg stands for enthalpy of saturated evaporation.
  • Both terms have units KJ/kg (kilo joule per kg).

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This might not help, But still will let you know more!

Explanation:

The Agricultural Revolution was a period of technological improvement and increased crop productivity that occurred during the 18th and early 19th centuries in Europe. In this lesson, learn the timeline, causes, effects and major inventions that spurred this shift in production.

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Convert the following decimal number to its equivalent binary ,octal,hexadecimal 1920​
Serhud [2]

Answer:

0b11110000000 is binary

0o3600 is in octal

0x780 in hexa dec.

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3 0
3 years ago
Write a program that generates two 3x3 matrices, A and B, withrandom values in the range [1, 100] and calculates the expression½
Alex

Answer:

#include <bits/stdc++.h>

using namespace std;

int main() {

int A[3][3],B[3][3],res[3][3],i,j;

srand(time(0));//for seed.

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

{

   int val=rand()%100+1;//generating random values in range 1 to 100.

   int val2=rand()%100+1;

   A[i][j]=val;

   B[i][j]=val2;

}

cout<<endl;

}

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       res[i][j]=0.5*A[i][j]+3*B[i][j];//storing the result in matrix res.

   }

}

cout<<"Matrix A is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<A[i][j]<<" ";//printing matrix A..

   }

   cout<<endl;

}

cout<<"Matrix B is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<B[i][j]<<" ";//printing matrix B..

   }

   cout<<endl;

}

cout<<"The result is"<<endl;

for(i=0;i<3;i++)

{

   for(j=0;j<3;j++)

   {

       cout<<res[i][j]<<" ";//printing the result..

   }

   cout<<endl;

}

return 0;

}

Output:-

Matrix A is

13 95 83  

88 7 14  

24 22 100  

Matrix B is

11 13 95  

48 35 20  

68 100 18  

The result is

39.5 86.5 326.5  

188 108.5 67  

216 311 104  

Explanation:

I have created 2 matrices A and B and storing random numbers int the matrices A and B.Then after that storing the result in res matrix of type double to store decimal values also.Then printing the res matrix.

6 0
3 years ago
i have a bag of trail mix . one half of the bag is peanuts. 1/4 of the bag is chocolate candies , and 1/4 of the bag is died fru
Lelu [443]
In our bag, 1/2 is peanuts, 1/4 is chocolate and 1/4 is dried fruit.

The likelihood of drawing a chocolate therefore is 1/4. 

The likelihood of drawing a peanut is 1/2 and the likelihood of drawing a dried fruit is 1/4.

Thus, D is the correct answer because the 1/4 likelihood of drawing a chocolate is less than the 1/2 chance of drawing a peanut.
8 0
3 years ago
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