Answer:
For Simple AAA. title games you can get a gtx 1050 ti which can run games decent about 60 fps on med to low settings i my self am running a r7 370 and i play FiveM at 40 fps or gta5 at 60 csgo at 120 fps if you want to go higher go with the best graphics and fps go with something cheap but extreme a RTX 2070 or 2080 and with ram it help the computer run smoother basically imagin what a plate is ram so more plates you have the more food you can store in it untill someone (the computer) uses it all its a quick storage for limited time the more the better usually for gaming a 16gb should be enough
Explanation:
The answer is C) Availability.
Although the company is addressing scalability by adding more servers, the question is asking for security requirement. Therefore we need to choose one of the principles from CIA triad which includes confidentiality, integrity, and availability.
Integrity involves keeping the data accurate and confidentiality involves keeping the data between the sender and intended recipient(s). That being said, scalability and availability are the possible answers.
C) Availability is the best answer because it is part of the CIA triad.
Note: Another resource to look at for cyber security principles would be the Parkerian Hexad.
Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
