Answer:
The major source of revenue for magazine company is "Advertising".
Explanation:
There are many source of income for magazine company such as subscription, circulations, advertisements.
From all above mentioned source of revenues, major source of revenues is advertising. Magazine companies publish different ads of different companies on title page as well as inside the magazine to generate the revenue.
Answer:
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- int num[] = new int[51];
- Scanner input = new Scanner(System.in);
- System.out.print("Number of input: ");
- int limit = input.nextInt();
- for(int i=0; i < limit; i++){
- System.out.print("Input a number (1-50): ");
- int k = input.nextInt();
- num[k]++;
- }
- for(int j=1; j < 51; j++){
- if(num[j] > 0){
- System.out.println("Number of occurrence of " + j + ": " + num[j]);
- }
- }
- }
- }
Explanation:
The solution is written in Java.
Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).
Create a Scanner object and get user entry the number of input (Line 6-7).
Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).
At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).
A text box is an object you can add to your document that lets you put and type text anywhere in your file. Text boxes can be useful for drawing attention to specific text and can also be helpful when you need to move text around in your document.
Lets first work out how many different codes would be needed to represent everything. 26 for lowercase, 26 for uppercase, and 10 for 0-9. Total, that makes 62 needed codes.
If we start with 0, we need to go up to 61 to represent all the characters. Thus, we can convert 61 to binary and count the number of digits needed to represent that as the last number in the set and that will tell us how many digits are needed.
61 in binary is 111101, so we need 6 digits to represent that number. The answer is B.
