Answer:
10 blocks
Step-by-step explanation:
Given
east
Required
Determine the shortest possible distance
To better explain my solution, I've added an attachment that illustrates her movement.
Using the attachment as a point of reference, the shortest distance is calculated by calculating the length of the hypotenuse using Pythagoras theorem.
So, we have:
Take positive square root of both sides
Answer:
Inverse Operations
Inverse operations
Division
Step-by-step explanation:
+4 on both sides
-17 both sides
Divide by 20 both sides.
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
it should be 100/3 or 33.3 repeating
