A group of students are intending to offer a present to a friend. If each one pays 3000 LL.

Mathematics

1 answer:

Elanso [62]2 years ago

3 0

Answer:

There are 8 friends and the presents costs $30,000

Step-by-step explanation:

Let x be the number of students and y be the price of the present. Their contributions can be expressed as:

$3000x=y-6000\ \ \ \ \ \ ...i\\\\4000x=y+2000\ \ \ \ \ \ \ \...ii$

#Make y the subject in equation i then substitute in ii:

$y=3000x+6000\\\\\#substitute \ in \ ii\\\\4000x=y+2000\\\\4000x=(3000x+6000)+2000\\\\1000x=8000\\\\x=8\\\\y=3000\times 8+6000\\\\y=30000$

Hence, there are 8 friends and the present is priced at $30,000

You might be interested in

What’s the answer<br> ..................... HELP

Anestetic [448]

Answer:7x+9

Step-by-step explanation:7x+6=3x+7=7x+9

6 0

2 years ago

1. Choose the best descriptor for the graph of f(x)=e^x+5.

Black_prince [1.1K]

Starting from a parent function $f(x)$ , if you add a constant to the whole function, i.e. you perform the transformation

$f(x) \to f(x)+k$

you shift the graph of the parent function by $k$ units, upwards if $k$ is positive, downwards otherwise.

In this case, so, you're shifting, the graph of $e^x$ 5 units upwards. Since the parent function passes through the point $(0,1)$ , because $e^0=1$ , the shifted graph mantains the same $x$ coordinate, but the $y$ coordinate is increased by 5, because of the 5 units upwards shift.